053a620e22
'local result=$(cmd)' resets $? to 0 (the local builtin's own exit), so the
following checkSuccess always saw success regardless of cmd's real exit — the
mechanism that masked the de-sudo write failures. Split declaration from
assignment ('local result; result=$(cmd)') across all 235 active-code sites
(84 files) so the command's exit reaches checkSuccess. No behaviour change
beyond $? now being accurate (no set -e in runtime code; multi-line
assignments transform safely).
Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
Signed-off-by: librelad <librelad@digitalangels.vip>
18 lines
761 B
Bash
Executable File
18 lines
761 B
Bash
Executable File
#!/bin/bash
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databaseOptionInsert()
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{
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local option="$1"
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local content="$2"
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local table_name=options
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local option_in_db=$(runInstallOp sqlite3 "$docker_dir/$db_file" "SELECT COUNT(*) FROM $table_name WHERE option = '$option';")
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if [ "$option_in_db" -eq 0 ]; then
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local result; result=$(runInstallOp sqlite3 "$docker_dir/$db_file" "INSERT INTO $table_name (option, content) VALUES ('$option', '$content');")
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checkSuccess "Adding $option to the $table_name table."
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else
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local result; result=$(runInstallOp sqlite3 "$docker_dir/$db_file" "UPDATE $table_name SET option = '$option', content = '$content';")
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checkSuccess "$option already added to the $table_name table. Updating content to $content."
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fi
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}
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