053a620e22
'local result=$(cmd)' resets $? to 0 (the local builtin's own exit), so the
following checkSuccess always saw success regardless of cmd's real exit — the
mechanism that masked the de-sudo write failures. Split declaration from
assignment ('local result; result=$(cmd)') across all 235 active-code sites
(84 files) so the command's exit reaches checkSuccess. No behaviour change
beyond $? now being accurate (no set -e in runtime code; multi-line
assignments transform safely).
Co-Authored-By: Claude Opus 4.8 <noreply@anthropic.com>
Signed-off-by: librelad <librelad@digitalangels.vip>
20 lines
842 B
Bash
Executable File
20 lines
842 B
Bash
Executable File
#!/bin/bash
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databasePortOpenInsert()
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{
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local app_name="$1"
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local portdata="$2"
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if [ -f "$docker_dir/$db_file" ] && [ -n "$app_name" ]; then
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local table_name=ports_open
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# Split the portdata into port and type
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IFS='/' read -r port type <<< "$portdata"
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# Check if already exists in the database
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local existing_portdata=$(runInstallOp sqlite3 "$docker_dir/$db_file" "SELECT port FROM $table_name WHERE name = '$app_name' AND port = '$port' AND type = '$type';")
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if [ -z "$existing_portdata" ]; then
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local result; result=$(runInstallOp sqlite3 "$docker_dir/$db_file" "INSERT INTO $table_name (name, port, type) VALUES ('$app_name', '$port', '$type');")
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checkSuccess "Adding port $port and type $type for $app_name to the $table_name table."
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fi
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fi
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}
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